How do you find the six trigonometric functions of 390 degrees? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer Nghi N. · EZ as pi Jun 3, 2015 390° = 360°+30° = 30° The ratios of 390 are the same as the ratios of 30°. Explanation: sin 390 = sin (30 + 360) = sin 30 = 1/2 cos 390 = cos (30 + 360) = cos 30 = sqrt3/2 tan 390 = tan 30 = 1/sqrt3 = sqrt3/3 cot 390 = 1/(tan 30) = sqrt3/1 sec 390 = 1/cos 30 = 2/sqrt3 csc 390 = 1/(sin 30) = 2/1 Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for 140^\circ? How do you find the value of cot 300^@? What is the value of sin -45^@? How do you find the trigonometric functions of values that are greater than 360^@? How do you use the reference angles to find sin210cos330-tan 135? How do you know if sin 30 = sin 150? How do you show that (costheta)(sectheta) = 1 if theta=pi/4? See all questions in Trigonometric Functions of Any Angle Impact of this question 34253 views around the world You can reuse this answer Creative Commons License