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How do you find the second derivative of #f(x)=3x^-2#?

1 Answer

Jan 30, 2017

#d^2/(dx^2) 3x^(-2) =18x^-4#

Explanation:

Using the power rule:

#d/(dx) 3x^(-2) = (-2)*3x^(-2-1) = -6x^(-3)#

#d^2/(dx^2) 3x^(-2) = d/(dx) -6x^-3 = (-3)*(-6)x^(-3-1) =18x^-4#

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