How do you find the derivative of $y = \sqrt{3 x}$ $y =sqrt(3x)$ ?

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Answer 1 · 2014-08-30T06:23:40

By General Power Rule (Power Rule and Chain Rule), $y'=3/{2sqrt{3x}}$ .

First, rewrite the square-root as the 1/2-power,
$y=(3x)^{1/2}$

By General Power Rule,
$y'=1/2(3x)^{-1/2}cdot 3={3}/{2sqrt{3x}}$

How do you find the derivative of y =sqrt(3x)y=√3xy =sqrt(3x)?