How do you find the roots, real and imaginary, of $y= x^2 -3x +7$ using the quadratic formula?

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How do you find the roots, real and imaginary, of $y= x^2 -3x +7$ using the quadratic formula?

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Answer 1 · 2016-02-07T23:31:14

the quadratic formula is:
$x_(1,2) = (-b+-sqrt(b^2-4ac))/(2a)$
$a= 1; b=-3; c=7$
If $sqrt(b^2-2ac)<0$ then you have an imaginary number.
Now Substitute and you're home free...

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How do you find the roots, real and imaginary, of $y= x^2 -3x +7$ using the quadratic formula?

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How do you find the roots, real and imaginary, of y= x^2 -3x +7 y= x^2 -3x +7 using the quadratic formula?

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How do you find the roots, real and imaginary, of $y= x^2 -3x +7$ using the quadratic formula?