How do you find the roots, real and imaginary, of $y=x^2 + -3x + 14$ using the quadratic formula?

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Answer 1 · 2018-05-26T09:58:48

$x_1=3/2+sqrt(47)/2i$ or $x_2=3/2-sqrt(47)/2i$

Using the formula
$x_{1,2}=-b/(2a)\pm1/(2a)sqrt(b^2-4ac}$
we get
$x_{1,2}=3/2pmsqrt(9/4-56/4)$
this gives
$x_{1,2}=3/2\pm\sqrt(47)/(2)i$

How do you find the roots, real and imaginary, of y=x^2 + -3x + 14 y=x^2 + -3x + 14 using the quadratic formula?