How do you find the roots, real and imaginary, of $y=x^2 + 3x + 1$ using the quadratic formula?

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How do you find the roots, real and imaginary, of $y=x^2 + 3x + 1$ using the quadratic formula?

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Answer 1 · 2015-12-23T12:51:00

Substitute the coefficients into the formula and evaluate. There are no imaginary roots

Explanation:

$y= (-b +- sqrt(b^2 - 4ac))/(2a)$ is the quadratic formula
In this example $a = 1$ , $b = 3$ and $c=1$
$y = (-3 +- sqrt(9 -4))/2$
$y = (-3-sqrt(5))/2$ or $y = -(-3+sqrt(5))/2$

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How do you find the roots, real and imaginary, of $y=x^2 + 3x + 1$ using the quadratic formula?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you find the roots, real and imaginary, of y=x^2 + 3x + 1 y=x^2 + 3x + 1 using the quadratic formula?

1 Answer

Explanation:

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Impact of this question

How do you find the roots, real and imaginary, of $y=x^2 + 3x + 1$ using the quadratic formula?