How do you find the roots, real and imaginary, of $y= x^2 - 2x-121$ using the quadratic formula?

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Answer 1 · 2016-01-03T12:38:22

$color(brown)({x_1 , x_2 } -> {41, -39})$

41, 39

Factorising gives: $y=(x-41)(x+39)$

Thus the roots are: $color(brown)({x_1 , x_2 } -> {41, -39})$

How do you find the roots, real and imaginary, of y= x^2 - 2x-121 y= x^2 - 2x-121 using the quadratic formula?