How do you find the roots, real and imaginary, of $y=8x^2-2x -5$ using the quadratic formula?

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Answer 1 · 2018-06-09T09:40:59

$color(orange)(x = (1 + sqrt31) / 8, (1 - sqrt31) / 8$

$y = 8x^2 - 2x - 5$

$a = 8, b = -2, c = -5$

$"quadratic formula is " x = (-b +- sqrt(b^2 - 4ac)) / (2a)$

$x = (2 +- sqrt(4 + 160)) / 16$

$x = (2 +- 2 sqrt31) / 16$

$color(orange)(x = (1 + sqrt31) / 8, (1 - sqrt31) / 8$

How do you find the roots, real and imaginary, of y=8x^2-2x -5y=8x^2-2x -5 using the quadratic formula?