How do you find the roots, real and imaginary, of y=7x^2-2x + 6 using the quadratic formula?

1 Answer
Nghi N.
Apr 11, 2016

(1 +- 6.4i)/7

Explanation:

y = 7x^2 - 2x + 6 = 0
Use the improved quadratic formula, also called the quadratic formula in intercept form (Google, Yahoo, Bing Search).
D = d^2 = b^2 - 4ac = 4 - 168 = -164 --> d = +- 12.80( i )
Since D < 0, there are no real roots. There are 2 complex roots -->
x = -b/(2a) +- d/(2a) = 2/14 +- (12.80i)/14 = (1 +- 6.4i)/7

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