How do you find the roots, real and imaginary, of $y=-6x^2 + 24x +24(x/2-1)^2$ using the quadratic formula?

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Answer 1 · 2017-12-07T22:33:24

No roots

First,we need to get this equation into Standard Form

$y = -6x^2+24x+24(x/2-1)^2$

$y = -6x^2+24x+24(x^2/4-x+1)$

$y = cancel(-6x^2)+cancel(24x)+cancel(6x^2)-cancel(24x)+24$

$y=24$

Well, I guess we don't need to use any quadratic formula for this

There are no roots for this, see

graph{y=24x/x}

It never crosses the $x-$ axis

How do you find the roots, real and imaginary, of y=-6x^2 + 24x +24(x/2-1)^2 y=-6x^2 + 24x +24(x/2-1)^2 using the quadratic formula?