How do you find the roots, real and imaginary, of $y= -5x^2 - 24x$ using the quadratic formula?

Question

1440 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-09T08:39:58

$;. x= (-b +- b) / (2a) = 0, -b / a = 0, -24/5$

#y = -5x^2 - 24x

$y = ax^2 + bx + c$ is the standard form.

$a = -5, b = -24, c = 0$

Since c = 0, discriminator $sqrt(b^2 - 4ac) = +-b$

$;. x= (-b +- b) / (2a) = 0, -b / a = 0, -24/5$

This can be verified by simplifying the equation

$y = -5x (x + 24/5)$

How do you find the roots, real and imaginary, of y= -5x^2 - 24x y= -5x^2 - 24x using the quadratic formula?