How do you find the roots, real and imaginary, of $y= -4x^2 + x^2 +6$ using the quadratic formula?

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Answer 1 · 2018-06-09T09:22:49

$color(indigo)("Roots are " x = -sqrt(3/2) , sqrt(3/2)$

$y = -4x^2 + x^2 + 6$

$y = -3x^2 + 6$

$a = -3, b = 0, c = 6$

$x = (0 +- sqrt(0 +96)) / -8$

$x = sqrt96/-8, sqrt96/8$

$color(indigo)("Roots are " x = -sqrt(3/2) , sqrt(3/2)$

How do you find the roots, real and imaginary, of y= -4x^2 + x^2 +6y= -4x^2 + x^2 +6 using the quadratic formula?