How do you find the roots, real and imaginary, of y=-3x^2 + -3x -4 using the quadratic formula?

1 Answer
Nghi N.
Jul 12, 2016

x = -1/2 +- (isqrt39)/6

Explanation:

Use the quadratic formula in graphic form (Google, Yahoo, Bing):
y = - 3x^2 - 3x - 4 = 0
D = d^2 = b^2 - 4ac = 9 - 48 = - 39 < 0 --> d = +- isqrt39
Since d < 0, there are 2 imaginary roots.
x = -b/(2a) +- d/(2a) = 3/-6 +- isqrt39/6 = -1/2 +- (isqrt39)/6

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