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How do you find the roots, real and imaginary, of #y= -3x^2 -2x +(2x+1)^2 # using the quadratic formula?

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1 Answer

Jul 24, 2018

#y=-3x^2-2x+(2x+1)^2# has a double root at #x=-1#

Explanation:

#y=-3x^2-2x+(2x+1)^2#
#y=-3x^2-2x+(4x^2+4x+1)#
#y=-3x^2-2x+4x^2+4x+1#
#y=x^2+2x+1#

Using the quadratic formula
#x=(-2+-sqrt(4-4(1)(1)))/(2)#
#x=(-2+-sqrt0)/2#
#x=(-2)/2#
#x=-1#

Therefore, #y=-3x^2-2x+(2x+1)^2# has a double root at #x=-1#

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