How do you find the roots, real and imaginary, of $y=2x² -452x-6$ using the quadratic formula?

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Answer 1 · 2017-07-11T23:43:26

$x=113+-2sqrt(3193)$

$y=2x^2-452-6$

Let $y=0$

$2x^2-452-6=0$

$x^2-226-3=0$

$x=(226+-sqrt(226^2-4(1)(3)))/2=(226+-4sqrt(3193))/2$

$=113+-2sqrt(3193)$

How do you find the roots, real and imaginary, of y=2x² -452x-6 y=2x² -452x-6 using the quadratic formula?