How do you find the roots, real and imaginary, of $y=-2x^2 + 7x +6$ using the quadratic formula?

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Answer 1 · 2015-12-01T17:38:41

Plug in a, b, c in the quadratic equation which is $((-b)+-sqrt(b^2-4ac))/(2a)$

$a=$ coefficient of $x^2$ .
$a=-2$

$b=$ coefficient of $x$ .
$b=7$

$c=$ the constant in the equation.
$c=6$

$((-7)+-sqrt((7)^2-4(-2)(6)))/(2(-2))$

How do you find the roots, real and imaginary, of y=-2x^2 + 7x +6 y=-2x^2 + 7x +6 using the quadratic formula?