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How do you find the roots, real and imaginary, of #y=-15x^2 +40x -4 # using the quadratic formula?

1 Answer

sankarankalyanam

Jun 9, 2018

#color(maroon)(" Roots are " x = 4/3 - sqrt(68/45), 4/3 + sqrt(68/45)#

Explanation:

#y = -15x^2 + 40x - 4#

#x = (-b +- sqrt(b^2 - 4ac)) / (2a)#

#a = -15, b = 40, c = -4#

#x = (-40 +- sqrt(1600 - 240)) / -30#

#x = (-40 +- sqrt1360) / - 30#

#color(maroon)("Roots are " x = 4/3 - sqrt(68/45), 4/3 + sqrt(68/45)#

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