How do you find the roots of $y=2x^2 – 9x + 55$ using the quadratic formula?

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Answer 1 · 2016-03-26T11:16:27

$x_1=(9+sqrt359i)/4=2.25+4.73682i$

$x_2=(9-sqrt359i)/4=2.25-4.73682i$

From the given equation $y=2x^2-9x+55$

We set $y=0$
Let $a=2$ and $b=-9$ and $c=55$

Quadratic Formula:
$x=(-b+-sqrt(b^2-4ac))/(2a)$

$x=(--9+-sqrt((-9)^2-4(2)(55)))/(2(2))$

$x=(+9+-sqrt(81-440))/(4)$

$x=(+9+-sqrt(-359))/(4)$

$x_1=(9+sqrt359i)/4=2.25+4.73682i$

$x_2=(9-sqrt359i)/4=2.25-4.73682i$

God bless....I hope the explanation is useful.

How do you find the roots of y=2x^2 – 9x + 55y=2x^2 – 9x + 55 using the quadratic formula?