How do you find the roots for $g(x) = x^2-x-12$ ?

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Answer 1 · 2017-05-23T22:45:12

$x=4$ and $x=-3$

We need to factor g(x):

$x^2-x-12$

$(x - 4)(x + 3)$

Now, we simply set each factor equal to zero and solve for x:

$x-4=0$
$x=4$

$x+3=0$
$x=-3$

How do you find the roots for g(x) = x^2-x-12g(x) = x^2-x-12?