How do you find the roots for 49x^2-14x-3?

1 Answer
Nghi N
Apr 4, 2018

- 1/7, and 3/7

Explanation:

Use the new Transforming Method (Socratic, Google Search):
y = 49x^2 - 14x - 3 = 0
Transformed equation:
y' = x^2 - 14x - 147 = 0
Method: Find 2 real roots of y', then, divide them by a = 49.
Find 2 real roots of y', that have opposite signs, knowing their sum (-b = 14) and their product (ac = - 147). They are -7, and 21.
The 2 real roots of y are:
x1 = -7/a = -7/49 = - 1/7, and x2 = 21/49 = 3/7

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