How do you find the remaining trigonometric functions of #theta# given #sintheta=-20/29# and #theta# terminates in QIII?

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How do you find the remaining trigonometric functions of #theta# given #sintheta=-20/29# and #theta# terminates in QIII?

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Answer 1 · 2017-04-25T13:29:59

#cos^2 t = 1 - sin^2 t = 1 - 400/841 = 441/841#
#cos t = +- 21/29#
Since t is in Quadrant 3, cos t is negative.
#cos t = - 21/19#
#tan t = sin/(cos) = (-20/29)(-29/21) = 20/21#
#cot t = 1/(tan) = 21/20#
#sec t = 1/(cos) = - 19/21#
#csc t = 1/(sin) = - 29/20#

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How do you find the remaining trigonometric functions of #theta# given #sintheta=-20/29# and #theta# terminates in QIII?

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