How do you find the rectangular equation for #r=5#?

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Answer 1 · 2016-11-21T01:41:38

Please see the explanation

Square both sides:

#r^2 = 5^2#

Substitute #x^2 + y^2# for #r^2#:

#x^2 + y^2 = 5^2#

Insert the center -0 into the x and y terms:

#(x - 0)^2 + (y - 0)^2 = 5^2#

This is the standard form for a circle whose center is #(0, 0)# and the radius is 5.