How do you find the quotient of m^2 – 3m – 28 ÷ m + 4?

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How do you find the quotient of m^2 – 3m – 28 ÷ m + 4?

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Answer 1 · 2015-12-25T10:43:37

To find the quotient of this particular problem, factorize $m^{2} - 3 m - 28$ $m^2-3m-28$ and divide the result by (m+4). The working and explanation given below.

Explanation:

There are many ways in which you can do this problem. If you are comfortable with factoring quadratic trinomials then the following way would be useful.

Our question is $m^{2} - 3 m - 28 \div m + 4$ $m^2-3m-28 -: m+4$

Let us rewrite it as $\frac{m^{2} - 3 m - 28}{m + 4}$ $(m^2-3m-28)/(m+4)$

Factoring the numerator : $m^{2} - 3 m - 28 = (m - 7) (m + 4)$ $m^2-3m-28 = (m-7)(m+4)$

$\frac{(m - 7) (m + 4)}{m + 4}$ $((m-7)(m+4))/(m+4)$
$((m-7)(cancel(m+4)))/(cancel(m+4)$ $=m-7$

The quotient is $m-7$

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How do you find the quotient of m^2 – 3m – 28 ÷ m + 4?

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Explanation:

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