How do you find the quotient of $(4x^2 – y^2) ÷ (2x – y)$ ?

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Answer 1 · 2015-10-29T04:34:42

$2x +y$

Note that

$(4x^2-y^2)/(2x-y)= ((cancel(2x-y))(2x+y))/(cancel(2x-y)) = 2x+y$

Since $a^2- b^2 = (a+b) (a-b)$

Answer 2 · 2015-10-29T04:37:59

(2x +y)

( 4 $x^2$ - $y^2$ ) / $(2x -y)$

( 4 $x^2$ - $y^2$ ) can be written as $( 2x +y) (2x -y)$

$(2x +y ) ( 2x-y) // (2x-y)$

$2x +y$

How do you find the quotient of (4x^2 – y^2) ÷ (2x – y)(4x^2 – y^2) ÷ (2x – y)?