How do you find the quotient of $(3 x^{2} + 4 x y + 3 x y + 4 y^{2}) \div (x + y)$ $(3x^2 + 4xy + 3xy + 4y^2) ÷ (x + y)$ ?

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How do you find the quotient of $(3 x^{2} + 4 x y + 3 x y + 4 y^{2}) \div (x + y)$ $(3x^2 + 4xy + 3xy + 4y^2) ÷ (x + y)$ ?

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Answer 1 · 2017-03-20T10:37:54

The remainder is $= 0$ $=0$ and the quotient is $= 3 x + 4 y$ $color(red)(=3x+4y$

Explanation:

$a a a a a a a$ $color(white)(aaaaaaa)$ $3 x + 4 y$ $color(red)(3x+4y$
$a a a a a a$ $color(white)(aaaaaa)$ $- - - - -$ $-----$
$a a a a a$ $color(white)(aaaaa)$ $∣$ $|$ $3 x^{2} + 7 x y + 4 y^{2}$ $3x^2+7xy +4y^2$
$a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaa)$ $3 x^{2} + 3 x y$ $3x^2+3xy$
$a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaa)$ $0 + 4 x y + 4 y^{2}$ $0+4xy+4y^2$
$a a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaaa)$ $4 x y + 4 y^{2}$ $4xy+4y^2$
$a a a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaaaa)$ $- - -$ $---$
$a a a a a a a a a a a a a a a a a a a$ $color(white)(aaaaaaaaaaaaaaaaaaa)$ $0 + 0$ $0+0$

The remainder is $= 0$ $=0$ and the quotient is $= 3 x + 4 y$ $color(red)(=3x+4y$

Answer 2 · 2017-03-20T10:39:42

$The Quotient= (3 x + 4 y) .$ $" The Quotient="(3x+4y).$

Explanation:

$ul(3x^2+4xy)+ul(3xy+4y^2),$

$=x(3x+4y)+y(3x+4y),$

$=(3x+4y)(x+y).$

$:. (3x^2+4xy+3xy+4y^2) -: (x+y),$

$=(3x^2+4xy+3xy+4y^2)/(x+y),$

$={(3x+4y)(cancel(x+y))}/(cancel(x+y)),$

$=(3x+4y)," is the desired quotient."$

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How do you find the quotient of $(3 x^{2} + 4 x y + 3 x y + 4 y^{2}) \div (x + y)$ $(3x^2 + 4xy + 3xy + 4y^2) ÷ (x + y)$ ?

2 Answers

Explanation:

Explanation:

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How do you find the quotient of (3x^2 + 4xy + 3xy + 4y^2) ÷ (x + y)(3x2+4xy+3xy+4y2)÷(x+y)(3x^2 + 4xy + 3xy + 4y^2) ÷ (x + y)?

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Explanation:

Explanation:

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How do you find the quotient of $(3 x^{2} + 4 x y + 3 x y + 4 y^{2}) \div (x + y)$ $(3x^2 + 4xy + 3xy + 4y^2) ÷ (x + y)$ ?