How do you find the product of #((k+6)(k-1))/(k+2)*((k+1)(k+2))/((k+1)(k-1))#?

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How do you find the product of #((k+6)(k-1))/(k+2)*((k+1)(k+2))/((k+1)(k-1))#?

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Answer 1 · 2017-04-23T08:47:10

#color(red)(k+6#

Explanation:

#((k+6)cancel((k-1)^color(red)1))/cancel((k+2)^color(red)1)*(cancel((k+1)^color(red)1)cancel((k+2)^color(red)1))/(cancel((k+1)^color(red)1)cancel((k-1)^color(red)1))#

#:.=k+6#

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How do you find the product of #((k+6)(k-1))/(k+2)*((k+1)(k+2))/((k+1)(k-1))#?

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