How do you find the product of #(d-1)(5d-4)#?

1 Answer
EZ as pi
Dec 21, 2016

#=5d^2-9d+4#

Explanation:

We have 2 factors which have to be multiplied. Each part of the first bracket has to be multiplied by each part of the second bracket. This is sometimes called the FOIL rule: "Firsts, Outers, Inners, Lasts"

#(color(blue)(d)color(red)(-1))(5d-4)#

#=color(blue)(d)(5d-4)color(red)(-1)(5d-4)#

#=color(blue)(5d^2-4d)color(red)(-5d+4)" "larr# collect the like terms

#=5d^2-9d+4" "larr# this is the product.

(It is a quadratic trinomial )

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