How do you find the product of $\frac{2 x^{3}}{7 x} \cdot \frac{14}{x}$ $(2x^3)/(7x)*14/x$ ?

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Answer 1 · 2017-04-15T20:08:48

$4 x$ $4x$

Since this is a multiplication, you can cancel out the 14 and the 7.

$\frac{2 x^{3}}{x} \cdot \frac{2}{x}$ $(2x^3)/(x)*2/x$

This equals to $\frac{4 x^{3}}{x^{2}}$ $(4x^3)/(x^2)$ and then to $4 x$ $4x$

This is because in a division, indices are subtracted, $3 - 2 = 1$ $3-2=1$ , leading to $4 x$ $4x$

How do you find the product of 2x37x⋅14x(2x^3)/(7x)*14/x?