How do you find the product #6*19#? Prealgebra Negative Numbers and Absolute Value Negative Numbers 1 Answer sjc · EZ as pi Jan 2, 2017 #114# Explanation: the product means multiply,so: #6*19=6xx19=114# one way of finding this product quickly is to do the following: #6xx19=6xx(20-1)# #=6xx20-6xx1# #=120-6=114# Answer link Related questions How do you compute #-8+13#? How do you compute #11+(-19)#? How do you compute #-19-8#? How do you compute #-77+(-46)#? How do you compute #41+(-56)#? How do you compute #50-82#? How do you compute #-47-13#? How do you compute #-80+102#? How do you compute #5(18)#? How do you compute #-64div(-8)#? See all questions in Negative Numbers Impact of this question 1812 views around the world You can reuse this answer Creative Commons License