How do you find the point (x,y) on the unit circle that corresponds to the real number #t=(11pi)/6#?

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How do you find the point (x,y) on the unit circle that corresponds to the real number #t=(11pi)/6#?

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Answer 1 · 2017-02-07T21:00:16

(#(sqrt3)/2#, -#1/2#)

Explanation:

#(11pi)/6# corresponds to 330 degrees on the unit circle, which also has the same point values as #pi/6#, but the y value is negative because it is in the 4th quadrant.

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How do you find the point (x,y) on the unit circle that corresponds to the real number #t=(11pi)/6#?

1 Answer

Explanation:

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