How do you find the point (x,y) on the unit circle that corresponds to the real number #t=pi/4#? Trigonometry Right Triangles Relating Trigonometric Functions 1 Answer sankarankalyanam Jun 17, 2018 #color(blue)((x,y) = (sqrt2/2, sqrt2/2) # or #color(blue)((1/sqrt2, 1/sqrt2)# Explanation: #t = pi/4# From the above diagram, #color(blue)((x,y) = (sqrt2/2, sqrt2/2) # or #color(blue)((1/sqrt2, 1/sqrt2)# Answer link Related questions What does it mean to find the sign of a trigonometric function and how do you find it? What are the reciprocal identities of trigonometric functions? What are the quotient identities for a trigonometric functions? What are the cofunction identities and reflection properties for trigonometric functions? What is the pythagorean identity? If #sec theta = 4#, how do you use the reciprocal identity to find #cos theta#? How do you find the domain and range of sine, cosine, and tangent? What quadrant does #cot 325^@# lie in and what is the sign? How do you use use quotient identities to explain why the tangent and cotangent function have... How do you show that #1+tan^2 theta = sec ^2 theta#? See all questions in Relating Trigonometric Functions Impact of this question 18970 views around the world You can reuse this answer Creative Commons License