How do you find the period of #y= tan 5 (theta)#?

1 Answer
Jim H
Jul 30, 2015

The period is #pi/5#

Explanation:

The base function: #f(x) = tanx# has period #pi#.

Multiplying by #5# before evaluating the tangent has the effect of compressing the period by dividing by #5#.

So the period of #y = tan(5theta)# is #pi/5#.

Similarity:
This case is similar to the period for #y = sin(3theta)#.
For the sine, the basic period is #2pi#, so the period of #y = sin(3theta)#.is #(2pi)/3#

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