How do you find the period of #tan(2pi x) #?

1 Answer
sankarankalyanam
Mar 19, 2018

See Below.

Explanation:

Standard form of equation is #y = A tan (Bx - C) + D#

Given #y = tan (2pix)#

#Amplitude = A = "None"# Function #tan x# doesn't have an amplitude.

#"Period " = P = pi / |B| = pi/ (2pi) = 1/2#

#" Phase Shift" = (-C) / B = 0 / (2pi) = 0#
#"Vertical Shift " = D = 0#

graph{tan(2pix) [-10, 10, -5, 5]}

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