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How do you find the period of #H = 10 + 4 sin (pi/6)(t)#?

1 Answer

A. S. Adikesavan

May 1, 2016

12.

Explanation:

The period of sin kt is #(2pi)/k# and so is the period of a + b sin kt.

Here, #k = pi/6, (2pi)/k=12#.

Check:
# H(t+12) =10+4 sin ((pi/6)(t+12))#
#=10+4sin((pi/6)t+2pi)#
#=10+4sin (pi/6)t#
#=H(t)#

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