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How do you find the period of #2 sin 3x#?

1 Answer

Jun 19, 2016

I found: #(2pi)/3#

Explanation:

You can "read" the period using the #3# in the argument of the #sin#; the period will then be:
#"period=(2pi)/color(red)(3)#

Graphically:
graph{2sin(3x) [-10, 10, -5, 5]}

Your #sin# function will repear each #(2pi)/3# radians.

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