How do you find the period for #y=20cos((2/3)x+pi)+2#?

1 Answer
Jim G.
May 30, 2018

#"period "=3pi#

Explanation:

#"the standard form of the cosine function is"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=acos(bx+c)+d)color(white)(2/2)|)))#

#"where amplitude "=|a|," period "=(2pi)/b#

#"phase shift "=-c/b" and vertical shift "=d#

#"here "b=2/3rArr"period "=(2pi)/(2/3)=3pi#

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