How do you find the period and amplitude of #y=1/3sin8x#?

1 Answer
Jim G.
Aug 5, 2017

#pi/4,1/3#

Explanation:

#"the standard form of the "color(blue)"sine function"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=asin(bx+c)+d)color(white)(2/2)|)))#

#"where amplitude "=|a|," period "=(2pi)/b#

#"phase shift "=-c/b," vertical shift "=d#

#"here "a=1/3,b=8,c=d=0#

#rArr"amplitude "=|1/3|=1/3," period "=(2pi)/8=pi/4#

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