How do you find the period and amplitude for #y= -4 sin((2x)/3)#?

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Answer 1 · 2018-08-08T01:02:41

#color(green)(Amplitude = 4, " Period " = 3pi#

Standard form of a sinusoidal function is #y = A sin (Bx - C) + D#

#"Given " y = -4 sin (2/3 x)#

#A = -4, B = 2/3, C = D = 0#

#Amplitude = |A| = |-4| = 4#

#"Period ' = (2pi) / |B| = (2pi) / (2/3) = 3 pi#

#"Phase Shift " = (-C/B) = 0#

#"Vertical Shift " = D = 0#

graph{-4 sin(2/3 x) [-10, 10, -5, 5]}