How do you find the partial sum of #Sigma 7n# from n=51 to 100? Calculus Introduction to Integration Sigma Notation 1 Answer Cem Sentin Nov 5, 2017 #x=7*(51+52+...+100)=26425# Explanation: #x=7*(51+52+...+100)# =#7*(100*101)/2#-#7*(50*51)/2# =#7*(5050-1275)# =#7*3775# =#26425# Answer link Related questions How does sigma notation work? How do you use sigma notation to represent the series #1/2+1/4+1/8+…#? Use summation notation to express the sum? What is sigma notation for an arithmetic series with first term #a# and common difference #d# ? How do you evaluate the sum represented by #sum_(n=1)^5n/(2n+1)# ? How do you evaluate the sum represented by #sum_(n=1)^(8)1/(n+1)# ? How do you evaluate the sum represented by #sum_(n=1)^(10)n^2# ? What is sigma notation for a geometric series with first term #a# and common ratio #r# ? What is the value of #1/n sum_{k=1}^n e^{k/n}# ? Question #07873 See all questions in Sigma Notation Impact of this question 3267 views around the world You can reuse this answer Creative Commons License