How do you find the nth term rule for $2,10,50,250,...$ ?

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Answer 1 · 2016-08-03T13:49:13

$n^(th)$ term = $t_n=2*5^(n-1)$ , where, $n in NN$ .

Let us note that, in the given seq., every succeeding term is obtained by multiplying by $5$ the preceding term.

In other words, this means that the given seq. is a Geometric Seq. with Common Ratio $r=5$ .

The seq. has the First Term $a=2$ .

The Formula for the General Term, or, $n^(th)$ term, denoted as $t_n$ is given by, $t_n=a*r^(n-1)$ .

In our case, $t_n=2*5^(n-1)$ , where, $n in NN$ .

How do you find the nth term rule for 2,10,50,250,...2,10,50,250,...?