How do you find the next two terms of the geometric sequence #81, 108, 144,...#? Precalculus Sequences Geometric Sequences 1 Answer Tony B Jan 1, 2017 192; 256 Explanation: #a_(i+1)=a_ixxr# #=>r=(a_(i+1))/a_i = 108/81 = 144/108 = 4/3# #a_1=81# #a_2=81xx4/3= 108# #a_3=108xx4/3=144# #a_4=144xx4/3= 192# #a_5=192xx4/3= 256# #a_n=81xx(4/3)^(n-1)# Answer link Related questions What is meant by a geometric sequence? What are common mistakes students make with geometric sequences? How do I find the equation of a geometric sequence? How do I find the first term of a geometric sequence? How do I find the common ratio of a geometric sequence? How can I recognize a geometric sequence? How do I use a geometric series to prove that #0.999...=1#? What is the common ratio of the geometric sequence 7, 28, 112,...? What is the common ratio of the geometric sequence 1, 4, 16, 64,...? What is the common ratio of the geometric sequence 2, 6, 18, 54,...? See all questions in Geometric Sequences Impact of this question 3861 views around the world You can reuse this answer Creative Commons License