How do you find the nature of the roots using the discriminant given 2x^2 + 7x - 3 = 0?

1 Answer
Binayaka C.
Jul 6, 2016

The roots are real: 0.386 , -3.886

Explanation:

Here in the quadratic equation of form ax^2+bx+c; a=2 ; b=7;c=-3 :.Discriminant d=b^2-4ac =7^2-(4*2*(-3))=73 since d>0 the roots are real. Roots= (-b+-sqrt(b^2-4ac))/(2a) :.root1= (-7+sqrt73)/4=0.386 and root2 =(-7-sqrt73)/4= -3.886[Ans]

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