How do you find the minimum value of a square root function f(x)= 3-sqrt(x+2)?

1 Answer
Jun 8, 2015

This one has no minimum value.

As x gets larger, the root gets larger, and the function as a whole becomes more and more negative (slowly but certainly).

Or, in "the language": lim_(x->oo) f(x)=-oo

It does have a maximum though:
The expression under the root may not be negative, it may be 0. This happens when x=-2->f(x)=3
graph{3-sqrt(x+2) [-3.85, 47.45, -12.5, 13.2]}

Domain: x>=-2
Range: f(x)<=3