Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you find the local max and min for #f(x) = 1 - sqrt(x)#?

1 Answer

Dec 15, 2016

Local maximum is #1# (at #x=0#).

Explanation:

#f'(x) = -1/(2sqrtx)#

#f'(x)# is never #0# and is undefined at #x=0# which is int he domain of #f#. So #0# is a critical number.

#f'# is not defined left of #0# and is negative #right of #0#, so #f(0) = 1# is a local maximum.

There are no other critical numbers, so there are no other local extrema.

Related questions

See all questions in Classifying Critical Points and Extreme Values for a Function

Impact of this question

6365 views around the world

You can reuse this answer
Creative Commons License