How do you find the linearization of the function z=xy at the point (-7, 64)?

1 Answer

The linear function that best aproximates z=xy at (7,64) is z=56+8(x+7)716(y64)=28+8x716y.

To get this result, we must first notice that z is a function of the two variables x and y. Let's write z=f(x,y). So, the best linear approximation Lr0(x,y) of f at r0=(x0,y0)=(7,64) is given by

Lr0(x,y)=f(x0,y0)+f(x0,y0)((x,y)(x0,y0))

Where f is the gradient of f and is the dot product.

Geometrically, this linear approxiamtion is the tangent plane of f at r0. The deduction of this equation is very similar to the deduction of the equation for the tangent line of a real function at a point, with the gradient f playing the role of the derivative.

Now we need to calculate the components of the equations for the linear aproximation. f(x0,y0) is simply the value of the function at (x0,y0):

f(x0,y0)=f(7,64)=7×64=56

The gradient f(x,y) of f is given by the expression

f(x,y)=(fx,fy)=(y,x2y)

So, f(x0,y0)=(64,7264)=(8,716)

Finally, we have:

Lr0(x,y)=56+(8,716)((x,y)(7,64))=
=56+(8,716)(x+7,y64)=
=56+8(x7)716(y64)=28+8x716y