How do you find the tangent line approximation to $f(x)=e^x$ near $x=0$ ?

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Answer 1 · 2014-09-24T04:19:59

We have to find the derivative of $f(x)$ and the input the x-value into the derivative to find the numeric slope.

$f(x)=e^x$

$f(0)=e^0=1$

Point of tangency is $(0,1)$ .

Note that we actually use the chain rule to find the derivative of $e^x$ .

$f'(x)=e^x*1=e^x$

$f'(0)=e^0=1 => slope or m$

How do you find the tangent line approximation to f(x)=e^xf(x)=e^x near x=0x=0 ?