How do you find the linearization of $f(x) = 2 ln(x)$ at the point a=1?

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Answer 1 · 2016-11-08T16:20:54

The linearization is the equation of the tangent line (often written in a particular form).

$f(x) = 2ln(x)$ at $x=1$ , f(1) = 0#

$f'(x) = 2/x$ , so $f'(1) = 2$

We get the linearization (and the tangent line) using

$y - f(a) = f'(a)(x-a)$

In this case $y = 0 + 2 (x-1)$ Rewrite to taste (or the taste of the person grading your work.)

How do you find the linearization of f(x) = 2 ln(x)f(x) = 2 ln(x) at the point a=1?