How do you find the linearization at a=1 of f(x) = ln(x)f(x)=ln(x)? Calculus Applications of Derivatives Using the Tangent Line to Approximate Function Values 1 Answer Jim H Nov 12, 2015 L=xL=x Explanation: L=f(a)+f'(a)(x-a) f(x) = lnx f(a) = f(1) =0 f'(x) = 1/x f'(a) = f'(1) = 1/1=1 L=x Answer link Related questions How do you find the linear approximation of (1.999)^4 ? How do you find the linear approximation of a function? How do you find the linear approximation of f(x)=ln(x) at x=1 ? How do you find the tangent line approximation for f(x)=sqrt(1+x) near x=0 ? How do you find the tangent line approximation to f(x)=1/x near x=1 ? How do you find the tangent line approximation to f(x)=cos(x) at x=pi/4 ? How do you find the tangent line approximation to f(x)=e^x near x=0 ? How do you use the tangent line approximation to approximate the value of ln(1003) ? How do you use the tangent line approximation to approximate the value of ln(1.006) ? How do you use the tangent line approximation to approximate the value of ln(1004) ? See all questions in Using the Tangent Line to Approximate Function Values Impact of this question 9969 views around the world You can reuse this answer Creative Commons License