How do you find the limit #(x^(1/4)-1)/x# as #x->1#?

Related questions

• How do you find the limit #lim_(x->5)(x^2-6x+5)/(x^2-25)# ?
• How do you find the limit #lim_(x->3^+)|3-x|/(x^2-2x-3)# ?
• How do you find the limit #lim_(x->4)(x^3-64)/(x^2-8x+16)# ?
• How do you find the limit #lim_(x->2)(x^2+x-6)/(x-2)# ?
• How do you find the limit #lim_(x->-4)(x^2+5x+4)/(x^2+3x-4)# ?
• How do you find the limit #lim_(t->-3)(t^2-9)/(2t^2+7t+3)# ?
• How do you find the limit #lim_(h->0)((4+h)^2-16)/h# ?
• How do you find the limit #lim_(h->0)((2+h)^3-8)/h# ?
• How do you find the limit #lim_(x->9)(9-x)/(3-sqrt(x))# ?
• How do you find the limit #lim_(h->0)(sqrt(1+h)-1)/h# ?