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How do you find the limit of #(x^5+3)/(x^2+4)# as #x->oo#?

1 Answer

Nov 13, 2017

#oo#

Explanation:

#(x^5+3)/(x^2+4)#

Divide by #x^2#

#(x^5/x^2+3/x^2)/(x^2/x^2+4/x^2)=(x^3/1+3/x^2)/(1+4/x^2)#

as #x->oo# , #(x^3/1+3/x^2)/(1+4/x^2)=(oo+0)/(1+0)->oo#

#:.#

#lim_(x->oo)((x^5+3)/(x^2+4))=oo#

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