How do you find the limit of $(x^5+3)/(x^2+4)$ as $x->oo$ ?

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Answer 1 · 2017-11-13T18:23:47

$oo$

$(x^5+3)/(x^2+4)$

Divide by $x^2$

$(x^5/x^2+3/x^2)/(x^2/x^2+4/x^2)=(x^3/1+3/x^2)/(1+4/x^2)$

as $x->oo$ , $(x^3/1+3/x^2)/(1+4/x^2)=(oo+0)/(1+0)->oo$

$:.$

$lim_(x->oo)((x^5+3)/(x^2+4))=oo$

How do you find the limit of (x^5+3)/(x^2+4)(x^5+3)/(x^2+4) as x->oox->oo?